TI-55 III Programs Part II: Impedance of a Series RLC Circuit, Quadratic Equation, Error Function
On to Part II!
For Part I, click here: Digital Root, Complex Number Multiplication, Escape Velocity
For Part III, click here: Area and Eccentricity of Ellipses, Determinant and Inverse of 2x2 Matrices, Speed of Sound/Principal Frequency
TI-55 III: Impedance of Series RLC Circuit
The impedance of a series RLC circuit in Ω (ohms) is:
Z = √(R^2 + (2*π*f*L – 1/(2*π*f*C))^2)
Where:
R = resistance of the resistor in ohms (Ω)
L = inductance of the inductor in Henrys (H)
C = capacitance of the capacitor in Farads (F)
f = resonance frequency in Hertz (Hz)
XL = 2*π*f*L
XC = 1/(2*π*f*C)
Program:
Partitions allowed: 1-4
STEP | CODE | KEY | COMMENT |
00 | 65 | * | Start with f |
01 | 02 | 2 | |
02 | 65 | * | |
03 | 91 | π | |
04 | 95 | = | |
05 | 61 | STO | |
06 | 00 | 0 | Store 2πf in R0 |
07 | 65 | * | |
08 | 12 | R/S | Prompt for L |
09 | 75 | - | |
10 | 53 | ( | |
11 | 71 | RCL | |
12 | 00 | 0 | |
13 | 65 | * | |
14 | 12 | R/S | Prompt for C |
15 | 54 | ) | |
16 | 17 | 1/x | |
18 | 18 | X^2 | |
19 | 85 | + | |
20 | 12 | R/S | Prompt for R |
21 | 18 | X^2 | |
22 | 95 | = | |
23 | 13 | √ | |
24 | 41 | INV | |
25 | 47 | Eng | Cancel Eng Notation |
26 | 12 | R/S | Display Z |
Input: f [RST] [R/S], L [R/S], C [R/S], R [R/S]
Result: Z
Test:
f = 60 Hz
L = 0.25 H
C = 16 * 10^-6 F
R = 150 Ω
Result: 166.18600 Ω
TI-55 III: Quadratic Equation
This program find the real roots of the equation:
X^2 + B*X + C = 0
Where:
D = B^2 – 4*C
If D ≥ 0, then continue the program since it will find the real roots. Otherwise, stop since the roots are complex and is beyond the scope of this program. The two roots are:
X1 = (-B + √D)/2
X2 = (-B - √D)/2
Program:
Partitions Allowed: 3
STEP | CODE | KEY | COMMENT |
00 | 71 | RCL | Calculate Discriminant |
01 | 00 | 0 | |
02 | 18 | X^2 | |
03 | 75 | - | |
04 | 04 | 4 | |
05 | 65 | * | |
06 | 71 | RCL | |
07 | 01 | 1 | |
08 | 95 | = | |
09 | 12 | R/S | Display Discriminant |
10 | 13 | √ | |
11 | 61 | STO | |
12 | 02 | 2 | |
13 | 75 | - | |
14 | 71 | RCL | |
15 | 00 | 0 | |
16 | 95 | = | |
17 | 55 | ÷ | |
18 | 02 | 2 | |
19 | 95 | = | |
20 | 12 | R/S | Display X1 |
21 | 53 | ( | |
22 | 71 | RCL | |
23 | 00 | 0 | |
24 | 85 | + | |
25 | 71 | RCL | |
26 | 02 | 2 | |
27 | 54 | ) | |
28 | 94 | +/- | |
29 | 55 | ÷ | |
30 | 02 | 2 | |
31 | 95 | = | |
32 | 12 | R/S | Display X2 |
Input: B [STO] 0, C [STO] 1, [RST] [R/S]
Results: Discriminant [R/S], root 1 [R/S], root 2
Test: Solve X^2 + 0.05*X – 1 = 0
Input: 0.05 [STO] 0, 1 [+/-] [STO] 1 [RST] [R/S]
Results: Discriminant = 4.0025 (It is non-negative, continue) [R/S]
X1 ≈ 0.9753125 [R/S]
X2 ≈ -1.0253125
TI-55 III: Gaussian Error Function
The error function is defined as:
erf(x) = ∫( 2*e^(-t^2)/√π dt, from t = 0 to t = x)
This program illustrates the integration function [ ∫ dx ] on the TI-55 III.
Program:
Prepare by pressing [2nd] [LRN] (Part) 3. Integration needs a minimum of 3 memory registers. That means, f(x) can take a maximum of 40 steps.
STEP | CODE | KEY | COMMENT |
00 | 18 | X^2 | Integrand |
01 | 94 | +/- | |
02 | 41 | INV | |
03 | 44 | ln x | [INV] [ln x]: e^x (EXP) |
04 | 65 | * | |
05 | 02 | 2 | |
06 | 55 | ÷ | |
07 | 91 | π | |
08 | 13 | √ | |
09 | 95 | = | |
10 | 12 | R/S | |
11 | 22 | RST | End f(x) with =,R/S,RST |
Input: 0 [STO] 1 (lower limit), x [STO] 2 (upper limit), [ ∫ dx ] n (number of partitions) [R/S]
Result: erf(x)
Test 1: erf(1.2) ≈ 0.910314. I use 12 partitions.
Input: 0 [STO] 1, 1.2 [STO] 2, [ ∫ dx ] 12 [ R/S ]
Result: 0.910314
Test 2: erf(0.9) ≈ 0.7969082. Store 0 in R0, 0.9 in R1. 12 partitions are used.
This blog is property of Edward Shore, 2016.
TI-55 III Programs Part II: Impedance of a Series RLC Circuit, Quadratic Equation, Error Function
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